How the MCAT tests organic reactions

Organic reactivity falls in AAMC content category 5D — the structure, function, and reactivity of biologically relevant molecules. The MCAT rarely asks for a synthesis; it asks you to read a mechanism, predict a product, or explain why one pathway wins. Thinking in terms of electron flow (nucleophile → electrophile) is the master skill.

workspace_premium The one lens

Find the electron-rich site (nucleophile) and the electron-poor site (electrophile). Curved arrows always start at electrons (a lone pair or bond) and point to where they go.

Nucleophiles, electrophiles, and leaving groups

These three roles define every polar reaction. A nucleophile donates an electron pair; an electrophile accepts one; a leaving group departs with the bonding electrons.

  • Good nucleophiles are electron-rich: negative charge, lone pairs, or π bonds (e.g., OH⁻, CN⁻, NH₃).
  • Electrophiles are electron-poor: partial-positive carbons, especially carbonyl carbons and carbons bearing a leaving group.
  • Good leaving groups are weak bases that are stable after leaving — halides (I⁻ > Br⁻ > Cl⁻), water, tosylate. OH⁻ and NH₂⁻ are poor leaving groups.

Nucleophilic substitution: SN1 vs SN2

In substitution, a nucleophile replaces a leaving group. The two pathways differ in timing and stereochemistry.

Nu:⁻ C LG backside attack → []‡ Nu C LG trigonal-bipyramidal TS → Nu C inverted product + LG:⁻ leaves configuration inverted (Walden inversion)
SN2 mechanism. The nucleophile attacks from the side opposite the leaving group in one concerted step, passing through a trigonal-bipyramidal transition state and inverting the stereocenter.
FeatureSN2SN1
StepsOne (concerted)Two (carbocation intermediate)
Rate lawSecond order: k[substrate][Nu]First order: k[substrate]
Best substrateMethyl / primaryTertiary (stable carbocation)
NucleophileStrongWeak (often solvent)
StereochemistryInversionRacemization

Steric access drives SN2; carbocation stability drives SN1.

Elimination: E1 vs E2

Elimination removes two groups to form a π bond (an alkene). It competes with substitution and is favored by heat and strong, bulky bases.

  • E2: one concerted step, second order, needs a strong base; the H and leaving group depart anti-periplanar. Follows Zaitsev (more substituted alkene) unless the base is bulky.
  • E1: two steps through a carbocation, first order, favored by weak bases and good ionizing solvents — parallels SN1.
  • Deciding factor: strong bulky base and heat → elimination; small strong nucleophile on a primary substrate → substitution.

Carbonyl chemistry

The carbonyl (C=O) is the most important functional group in organic and biochemistry. Its carbon is electrophilic, so nucleophiles add across the double bond.

C O δ− δ+ Nu:⁻ → C O⁻ Nu tetrahedral alkoxide The carbonyl carbon is electrophilic (δ+); the nucleophile adds there.
Nucleophilic addition. A nucleophile attacks the electrophilic carbonyl carbon, breaking the π bond and giving a tetrahedral alkoxide intermediate.
workspace_premium Reactivity of derivatives

Carboxylic-acid derivatives react by addition–elimination, and their reactivity follows leaving-group ability: acyl chloride > anhydride > ester ≈ carboxylic acid > amide. A more reactive derivative can be converted into a less reactive one, but not the reverse.

Oxidation and reduction

In organic chemistry, oxidation increases bonds to oxygen (or other heteroatoms) and reduction increases bonds to hydrogen. The alcohol → aldehyde → carboxylic acid ladder is the classic sequence.

1° AlcoholR–CH₂OHAldehydeR–CHOCarboxylic acidR–COOH [O] [H] [O] [H] Oxidation adds C–O bonds (gold, →); reduction adds C–H bonds (blue, ←).
The oxidation ladder. A primary alcohol oxidizes to an aldehyde and then a carboxylic acid; reducing agents run the sequence backward.
  • Oxidizing agents (PCC stops at the aldehyde; strong agents like chromic acid go to the carboxylic acid).
  • Reducing agents (LiAlH₄ is strong and reduces esters/acids to alcohols; NaBH₄ is milder, reducing aldehydes and ketones).
  • Secondary alcohols oxidize to ketones, which resist further oxidation.

How to study it — and the traps to avoid

Organic reactions are learned by drawing electron flow, not by rote lists. Practice curved-arrow pushing until it is automatic.

  1. For every reaction, label the nucleophile, electrophile, and leaving group first.
  2. Decide SN1/SN2/E1/E2 from substrate class, nucleophile/base strength, and conditions.
  3. Remember SN2 inverts configuration; SN1 racemizes.
  4. Track oxidation state by counting bonds to O versus H.
error Highest-yield trap

Do not treat a strong base as a good nucleophile automatically. A strong, bulky base (like tert-butoxide) mostly does E2 elimination rather than SN2 substitution because it is too hindered to attack carbon directly.